10[z-(2z+19)+10]=2(z+9)

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Solution for 10[z-(2z+19)+10]=2(z+9) equation:


Simplifying
10[z + -1(2z + 19) + 10] = 2(z + 9)

Reorder the terms:
10[z + -1(19 + 2z) + 10] = 2(z + 9)
10[z + (19 * -1 + 2z * -1) + 10] = 2(z + 9)
10[z + (-19 + -2z) + 10] = 2(z + 9)

Reorder the terms:
10[-19 + 10 + z + -2z] = 2(z + 9)

Combine like terms: -19 + 10 = -9
10[-9 + z + -2z] = 2(z + 9)

Combine like terms: z + -2z = -1z
10[-9 + -1z] = 2(z + 9)
[-9 * 10 + -1z * 10] = 2(z + 9)
[-90 + -10z] = 2(z + 9)

Reorder the terms:
-90 + -10z = 2(9 + z)
-90 + -10z = (9 * 2 + z * 2)
-90 + -10z = (18 + 2z)

Solving
-90 + -10z = 18 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
-90 + -10z + -2z = 18 + 2z + -2z

Combine like terms: -10z + -2z = -12z
-90 + -12z = 18 + 2z + -2z

Combine like terms: 2z + -2z = 0
-90 + -12z = 18 + 0
-90 + -12z = 18

Add '90' to each side of the equation.
-90 + 90 + -12z = 18 + 90

Combine like terms: -90 + 90 = 0
0 + -12z = 18 + 90
-12z = 18 + 90

Combine like terms: 18 + 90 = 108
-12z = 108

Divide each side by '-12'.
z = -9

Simplifying
z = -9

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